1 /* Copyright (C) 1991, 1993, 1996, 1997, 1999, 2000, 2003, 2004 Free
2    Software Foundation, Inc.
3 
4    Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
5    with help from Dan Sahlin (dan@sics.se) and
6    commentary by Jim Blandy (jimb@ai.mit.edu);
7    adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
8    and implemented by Roland McGrath (roland@ai.mit.edu).
9 
10 NOTE: The canonical source of this file is maintained with the GNU C Library.
11 Bugs can be reported to bug-glibc@prep.ai.mit.edu.
12 
13 This program is free software; you can redistribute it and/or modify it
14 under the terms of the GNU General Public License as published by the
15 Free Software Foundation; either version 2, or (at your option) any
16 later version.
17 
18 This program is distributed in the hope that it will be useful,
19 but WITHOUT ANY WARRANTY; without even the implied warranty of
20 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
21 GNU General Public License for more details.
22 
23 You should have received a copy of the GNU General Public License
24 along with this program; if not, write to the Free Software Foundation,
25 Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA.  */
26 #include <sys/cdefs.h>
27 __RCSID("$NetBSD: memchr.c,v 1.2 2016/05/17 14:00:09 christos Exp $");
28 
29 
30 #ifdef HAVE_CONFIG_H
31 # include <config.h>
32 #endif
33 
34 #include <string.h>
35 
36 #include <stddef.h>
37 
38 #if defined _LIBC
39 # include <memcopy.h>
40 #else
41 # define reg_char char
42 #endif
43 
44 #include <limits.h>
45 
46 #if HAVE_BP_SYM_H || defined _LIBC
47 # include <bp-sym.h>
48 #else
49 # define BP_SYM(sym) sym
50 #endif
51 
52 #undef memchr
53 #undef __memchr
54 
55 /* Search no more than N bytes of S for C.  */
56 void *
__memchr(void const * s,int c_in,size_t n)57 __memchr (void const *s, int c_in, size_t n)
58 {
59   const unsigned char *char_ptr;
60   const unsigned long int *longword_ptr;
61   unsigned long int longword, magic_bits, charmask;
62   unsigned reg_char c;
63   int i;
64 
65   c = (unsigned char) c_in;
66 
67   /* Handle the first few characters by reading one character at a time.
68      Do this until CHAR_PTR is aligned on a longword boundary.  */
69   for (char_ptr = (const unsigned char *) s;
70        n > 0 && (size_t) char_ptr % sizeof longword != 0;
71        --n, ++char_ptr)
72     if (*char_ptr == c)
73       return (void *) char_ptr;
74 
75   /* All these elucidatory comments refer to 4-byte longwords,
76      but the theory applies equally well to any size longwords.  */
77 
78   longword_ptr = (const unsigned long int *) char_ptr;
79 
80   /* Bits 31, 24, 16, and 8 of this number are zero.  Call these bits
81      the "holes."  Note that there is a hole just to the left of
82      each byte, with an extra at the end:
83 
84      bits:  01111110 11111110 11111110 11111111
85      bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
86 
87      The 1-bits make sure that carries propagate to the next 0-bit.
88      The 0-bits provide holes for carries to fall into.  */
89 
90   /* Set MAGIC_BITS to be this pattern of 1 and 0 bits.
91      Set CHARMASK to be a longword, each of whose bytes is C.  */
92 
93   magic_bits = 0xfefefefe;
94   charmask = c | (c << 8);
95   charmask |= charmask << 16;
96 #if 0xffffffffU < ULONG_MAX
97   magic_bits |= magic_bits << 32;
98   charmask |= charmask << 32;
99   if (8 < sizeof longword)
100     for (i = 64; i < sizeof longword * 8; i *= 2)
101       {
102           magic_bits |= magic_bits << i;
103           charmask |= charmask << i;
104       }
105 #endif
106   magic_bits = (ULONG_MAX >> 1) & (magic_bits | 1);
107 
108   /* Instead of the traditional loop which tests each character,
109      we will test a longword at a time.  The tricky part is testing
110      if *any of the four* bytes in the longword in question are zero.  */
111   while (n >= sizeof longword)
112     {
113       /* We tentatively exit the loop if adding MAGIC_BITS to
114            LONGWORD fails to change any of the hole bits of LONGWORD.
115 
116            1) Is this safe?  Will it catch all the zero bytes?
117            Suppose there is a byte with all zeros.  Any carry bits
118            propagating from its left will fall into the hole at its
119            least significant bit and stop.  Since there will be no
120            carry from its most significant bit, the LSB of the
121            byte to the left will be unchanged, and the zero will be
122            detected.
123 
124            2) Is this worthwhile?  Will it ignore everything except
125            zero bytes?  Suppose every byte of LONGWORD has a bit set
126            somewhere.  There will be a carry into bit 8.  If bit 8
127            is set, this will carry into bit 16.  If bit 8 is clear,
128            one of bits 9-15 must be set, so there will be a carry
129            into bit 16.  Similarly, there will be a carry into bit
130            24.  If one of bits 24-30 is set, there will be a carry
131            into bit 31, so all of the hole bits will be changed.
132 
133            The one misfire occurs when bits 24-30 are clear and bit
134            31 is set; in this case, the hole at bit 31 is not
135            changed.  If we had access to the processor carry flag,
136            we could close this loophole by putting the fourth hole
137            at bit 32!
138 
139            So it ignores everything except 128's, when they're aligned
140            properly.
141 
142            3) But wait!  Aren't we looking for C, not zero?
143            Good point.  So what we do is XOR LONGWORD with a longword,
144            each of whose bytes is C.  This turns each byte that is C
145            into a zero.  */
146 
147       longword = *longword_ptr++ ^ charmask;
148 
149       /* Add MAGIC_BITS to LONGWORD.  */
150       if ((((longword + magic_bits)
151 
152               /* Set those bits that were unchanged by the addition.  */
153               ^ ~longword)
154 
155              /* Look at only the hole bits.  If any of the hole bits
156                 are unchanged, most likely one of the bytes was a
157                 zero.  */
158              & ~magic_bits) != 0)
159           {
160             /* Which of the bytes was C?  If none of them were, it was
161                a misfire; continue the search.  */
162 
163             const unsigned char *cp = (const unsigned char *) (longword_ptr - 1);
164 
165             if (cp[0] == c)
166               return (void *) cp;
167             if (cp[1] == c)
168               return (void *) &cp[1];
169             if (cp[2] == c)
170               return (void *) &cp[2];
171             if (cp[3] == c)
172               return (void *) &cp[3];
173             if (4 < sizeof longword && cp[4] == c)
174               return (void *) &cp[4];
175             if (5 < sizeof longword && cp[5] == c)
176               return (void *) &cp[5];
177             if (6 < sizeof longword && cp[6] == c)
178               return (void *) &cp[6];
179             if (7 < sizeof longword && cp[7] == c)
180               return (void *) &cp[7];
181             if (8 < sizeof longword)
182               for (i = 8; i < sizeof longword; i++)
183                 if (cp[i] == c)
184                     return (void *) &cp[i];
185           }
186 
187       n -= sizeof longword;
188     }
189 
190   char_ptr = (const unsigned char *) longword_ptr;
191 
192   while (n-- > 0)
193     {
194       if (*char_ptr == c)
195           return (void *) char_ptr;
196       else
197           ++char_ptr;
198     }
199 
200   return 0;
201 }
202 #ifdef weak_alias
203 weak_alias (__memchr, BP_SYM (memchr))
204 #endif
205