xref: /dragonfly/crypto/libressl/crypto/bn/bn_recp.c (revision 72c3367655e64985522b7a48ddfab613e869dc68)
1 /* $OpenBSD: bn_recp.c,v 1.15 2017/01/29 17:49:22 beck Exp $ */
2 /* Copyright (C) 1995-1998 Eric Young (eay@cryptsoft.com)
3  * All rights reserved.
4  *
5  * This package is an SSL implementation written
6  * by Eric Young (eay@cryptsoft.com).
7  * The implementation was written so as to conform with Netscapes SSL.
8  *
9  * This library is free for commercial and non-commercial use as long as
10  * the following conditions are aheared to.  The following conditions
11  * apply to all code found in this distribution, be it the RC4, RSA,
12  * lhash, DES, etc., code; not just the SSL code.  The SSL documentation
13  * included with this distribution is covered by the same copyright terms
14  * except that the holder is Tim Hudson (tjh@cryptsoft.com).
15  *
16  * Copyright remains Eric Young's, and as such any Copyright notices in
17  * the code are not to be removed.
18  * If this package is used in a product, Eric Young should be given attribution
19  * as the author of the parts of the library used.
20  * This can be in the form of a textual message at program startup or
21  * in documentation (online or textual) provided with the package.
22  *
23  * Redistribution and use in source and binary forms, with or without
24  * modification, are permitted provided that the following conditions
25  * are met:
26  * 1. Redistributions of source code must retain the copyright
27  *    notice, this list of conditions and the following disclaimer.
28  * 2. Redistributions in binary form must reproduce the above copyright
29  *    notice, this list of conditions and the following disclaimer in the
30  *    documentation and/or other materials provided with the distribution.
31  * 3. All advertising materials mentioning features or use of this software
32  *    must display the following acknowledgement:
33  *    "This product includes cryptographic software written by
34  *     Eric Young (eay@cryptsoft.com)"
35  *    The word 'cryptographic' can be left out if the rouines from the library
36  *    being used are not cryptographic related :-).
37  * 4. If you include any Windows specific code (or a derivative thereof) from
38  *    the apps directory (application code) you must include an acknowledgement:
39  *    "This product includes software written by Tim Hudson (tjh@cryptsoft.com)"
40  *
41  * THIS SOFTWARE IS PROVIDED BY ERIC YOUNG ``AS IS'' AND
42  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
43  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
44  * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
45  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
46  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
47  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
48  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
49  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
50  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
51  * SUCH DAMAGE.
52  *
53  * The licence and distribution terms for any publically available version or
54  * derivative of this code cannot be changed.  i.e. this code cannot simply be
55  * copied and put under another distribution licence
56  * [including the GNU Public Licence.]
57  */
58 
59 #include <stdio.h>
60 
61 #include <openssl/err.h>
62 
63 #include "bn_lcl.h"
64 
65 void
BN_RECP_CTX_init(BN_RECP_CTX * recp)66 BN_RECP_CTX_init(BN_RECP_CTX *recp)
67 {
68           BN_init(&(recp->N));
69           BN_init(&(recp->Nr));
70           recp->num_bits = 0;
71           recp->flags = 0;
72 }
73 
74 BN_RECP_CTX *
BN_RECP_CTX_new(void)75 BN_RECP_CTX_new(void)
76 {
77           BN_RECP_CTX *ret;
78 
79           if ((ret = malloc(sizeof(BN_RECP_CTX))) == NULL)
80                     return (NULL);
81 
82           BN_RECP_CTX_init(ret);
83           ret->flags = BN_FLG_MALLOCED;
84           return (ret);
85 }
86 
87 void
BN_RECP_CTX_free(BN_RECP_CTX * recp)88 BN_RECP_CTX_free(BN_RECP_CTX *recp)
89 {
90           if (recp == NULL)
91                     return;
92 
93           BN_free(&(recp->N));
94           BN_free(&(recp->Nr));
95           if (recp->flags & BN_FLG_MALLOCED)
96                     free(recp);
97 }
98 
99 int
BN_RECP_CTX_set(BN_RECP_CTX * recp,const BIGNUM * d,BN_CTX * ctx)100 BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)
101 {
102           if (!BN_copy(&(recp->N), d))
103                     return 0;
104           BN_zero(&(recp->Nr));
105           recp->num_bits = BN_num_bits(d);
106           recp->shift = 0;
107           return (1);
108 }
109 
110 int
BN_mod_mul_reciprocal(BIGNUM * r,const BIGNUM * x,const BIGNUM * y,BN_RECP_CTX * recp,BN_CTX * ctx)111 BN_mod_mul_reciprocal(BIGNUM *r, const BIGNUM *x, const BIGNUM *y,
112     BN_RECP_CTX *recp, BN_CTX *ctx)
113 {
114           int ret = 0;
115           BIGNUM *a;
116           const BIGNUM *ca;
117 
118           BN_CTX_start(ctx);
119           if ((a = BN_CTX_get(ctx)) == NULL)
120                     goto err;
121           if (y != NULL) {
122                     if (x == y) {
123                               if (!BN_sqr(a, x, ctx))
124                                         goto err;
125                     } else {
126                               if (!BN_mul(a, x, y, ctx))
127                                         goto err;
128                     }
129                     ca = a;
130           } else
131                     ca = x; /* Just do the mod */
132 
133           ret = BN_div_recp(NULL, r, ca, recp, ctx);
134 
135 err:
136           BN_CTX_end(ctx);
137           bn_check_top(r);
138           return (ret);
139 }
140 
141 int
BN_div_recp(BIGNUM * dv,BIGNUM * rem,const BIGNUM * m,BN_RECP_CTX * recp,BN_CTX * ctx)142 BN_div_recp(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m, BN_RECP_CTX *recp,
143     BN_CTX *ctx)
144 {
145           int i, j, ret = 0;
146           BIGNUM *a, *b, *d, *r;
147 
148           BN_CTX_start(ctx);
149           a = BN_CTX_get(ctx);
150           b = BN_CTX_get(ctx);
151           if (dv != NULL)
152                     d = dv;
153           else
154                     d = BN_CTX_get(ctx);
155           if (rem != NULL)
156                     r = rem;
157           else
158                     r = BN_CTX_get(ctx);
159           if (a == NULL || b == NULL || d == NULL || r == NULL)
160                     goto err;
161 
162           if (BN_ucmp(m, &(recp->N)) < 0) {
163                     BN_zero(d);
164                     if (!BN_copy(r, m)) {
165                               BN_CTX_end(ctx);
166                               return 0;
167                     }
168                     BN_CTX_end(ctx);
169                     return (1);
170           }
171 
172           /* We want the remainder
173            * Given input of ABCDEF / ab
174            * we need multiply ABCDEF by 3 digests of the reciprocal of ab
175            *
176            */
177 
178           /* i := max(BN_num_bits(m), 2*BN_num_bits(N)) */
179           i = BN_num_bits(m);
180           j = recp->num_bits << 1;
181           if (j > i)
182                     i = j;
183 
184           /* Nr := round(2^i / N) */
185           if (i != recp->shift)
186                     recp->shift = BN_reciprocal(&(recp->Nr), &(recp->N), i, ctx);
187 
188           /* BN_reciprocal returns i, or -1 for an error */
189           if (recp->shift == -1)
190                     goto err;
191 
192           /* d := |round(round(m / 2^BN_num_bits(N)) * recp->Nr / 2^(i - BN_num_bits(N)))|
193            *    = |round(round(m / 2^BN_num_bits(N)) * round(2^i / N) / 2^(i - BN_num_bits(N)))|
194            *   <= |(m / 2^BN_num_bits(N)) * (2^i / N) * (2^BN_num_bits(N) / 2^i)|
195            *    = |m/N|
196            */
197           if (!BN_rshift(a, m, recp->num_bits))
198                     goto err;
199           if (!BN_mul(b, a,&(recp->Nr), ctx))
200                     goto err;
201           if (!BN_rshift(d, b, i - recp->num_bits))
202                     goto err;
203           d->neg = 0;
204 
205           if (!BN_mul(b, &(recp->N), d, ctx))
206                     goto err;
207           if (!BN_usub(r, m, b))
208                     goto err;
209           r->neg = 0;
210 
211 #if 1
212           j = 0;
213           while (BN_ucmp(r, &(recp->N)) >= 0) {
214                     if (j++ > 2) {
215                               BNerror(BN_R_BAD_RECIPROCAL);
216                               goto err;
217                     }
218                     if (!BN_usub(r, r, &(recp->N)))
219                               goto err;
220                     if (!BN_add_word(d, 1))
221                               goto err;
222           }
223 #endif
224 
225           r->neg = BN_is_zero(r) ? 0 : m->neg;
226           d->neg = m->neg^recp->N.neg;
227           ret = 1;
228 
229 err:
230           BN_CTX_end(ctx);
231           bn_check_top(dv);
232           bn_check_top(rem);
233           return (ret);
234 }
235 
236 /* len is the expected size of the result
237  * We actually calculate with an extra word of precision, so
238  * we can do faster division if the remainder is not required.
239  */
240 /* r := 2^len / m */
241 int
BN_reciprocal(BIGNUM * r,const BIGNUM * m,int len,BN_CTX * ctx)242 BN_reciprocal(BIGNUM *r, const BIGNUM *m, int len, BN_CTX *ctx)
243 {
244           int ret = -1;
245           BIGNUM *t;
246 
247           BN_CTX_start(ctx);
248           if ((t = BN_CTX_get(ctx)) == NULL)
249                     goto err;
250 
251           if (!BN_set_bit(t, len))
252                     goto err;
253 
254           if (!BN_div_ct(r, NULL, t,m, ctx))
255                     goto err;
256 
257           ret = len;
258 
259 err:
260           bn_check_top(r);
261           BN_CTX_end(ctx);
262           return (ret);
263 }
264