Searched refs:lastpenalty (Results 1 – 9 of 9) sorted by relevance
1410 route->lastpenalty = time(NULL); in mta_route_disable()1444 route->lastpenalty = time(NULL); in mta_route_enable()2489 sched = r->lastpenalty + delay; in mta_route_unref()
764 time_t lastpenalty; member
253 % add check for \lastpenalty to plain's definitions. If the last thing256 \def\smallbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\smallskipamount258 \def\medbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\medskipamount260 \def\bigbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\bigskipamount2356 \ifnum\lastpenalty<10000 \parskip=0in \fi3355 % \lastskip and \lastpenalty cannot both be nonzero simultaneously.3358 \count255 = \lastpenalty4655 \ifnum \lastpenalty=10000 \else4662 \ifnum\lastpenalty<10000 \penalty-50 \fi5049 % then it can also check if \lastpenalty=1. If it does, then manually[all …]
264 % add check for \lastpenalty to plain's definitions. If the last thing267 \def\smallbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\smallskipamount269 \def\medbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\medskipamount271 \def\bigbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\bigskipamount2568 \ifnum\lastpenalty<10000 \parskip=0in \fi3583 % \lastskip and \lastpenalty cannot both be nonzero simultaneously.3586 \count255 = \lastpenalty4922 \ifnum \lastpenalty=10000 \else4929 \ifnum\lastpenalty<10000 \penalty-50 \fi5310 \ifnum\lastpenalty<10000[all …]
256 % add check for \lastpenalty to plain's definitions. If the last thing259 \def\smallbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\smallskipamount261 \def\medbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\medskipamount263 \def\bigbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\bigskipamount2467 \ifnum\lastpenalty<10000 \parskip=0in \fi3481 % \lastskip and \lastpenalty cannot both be nonzero simultaneously.3484 \count255 = \lastpenalty4798 \ifnum \lastpenalty=10000 \else4805 \ifnum\lastpenalty<10000 \penalty-50 \fi5186 \ifnum\lastpenalty<10000[all …]
206 % add check for \lastpenalty to plain's definitions. If the last thing209 \def\smallbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\smallskipamount211 \def\medbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\medskipamount213 \def\bigbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\bigskipamount3285 \count255=\lastpenalty4538 \ifnum \lastpenalty=10000 \else4545 \ifnum\lastpenalty>10000 \else \penalty-50 \fi4941 % then it can also check if \lastpenalty=1. If it does, then manually4956 \ifnum \lastpenalty=1 %5101 \ifnum\lastpenalty=10002 \penalty0 \fi[all …]
4590 all, purely to make \lastpenalty 10000 so future code can check4593 \medbreak if lastpenalty >=10000.
9987 \ifnum\lastpenalty to plain tex definitions, so that we won't9989 (\aboveenvbreak): similar check of \lastpenalty.
2882 \count255=\lastpenalty