Searched refs:sub_last_idx (Results 1 – 1 of 1) sorted by relevance
2695 Idx sub_last_idx, sl_str, bkref_str_off; in get_subexp() local2704 for (sub_last_idx = 0; sub_last_idx < sub_top->nlasts; ++sub_last_idx) in get_subexp()2707 sub_last = sub_top->lasts[sub_last_idx]; in get_subexp()2744 if (sub_last_idx < sub_top->nlasts) in get_subexp()2746 if (sub_last_idx > 0) in get_subexp()