Searched refs:Freq (Results 1 – 2 of 2) sorted by relevance
415 for (n = 0; n < L_CODES; n++) s->dyn_ltree[n].Freq = 0;416 for (n = 0; n < D_CODES; n++) s->dyn_dtree[n].Freq = 0;417 for (n = 0; n < BL_CODES; n++) s->bl_tree[n].Freq = 0;419 s->dyn_ltree[END_BLOCK].Freq = 1;444 (tree[n].Freq < tree[m].Freq || \445 (tree[n].Freq == tree[m].Freq && depth[n] <= depth[m]))524 f = tree[n].Freq;559 *(long)tree[m].Freq;635 if (tree[n].Freq != 0) {650 tree[node].Freq = 1;[all …]
76 #define Freq fc.freq macro327 s->dyn_ltree[cc].Freq++; \336 s->dyn_ltree[_length_code[len]+LITERALS+1].Freq++; \337 s->dyn_dtree[d_code(dist)].Freq++; \