Searched refs:leapyear (Results 1 – 2 of 2) sorted by relevance
90 #define days_in_year(y) (leapyear(y) ? 366 : 365)92 (month_days[(m) - 1] + (m == FEBRUARY ? leapyear(y) : 0))110 leapyear(int year) in leapyear() function
892 int leapyear; local898 leapyear = isleap(year);910 if (leapyear && rulep->r_day >= 60)929 value += mon_lengths[leapyear][i] * SECSPERDAY;954 mon_lengths[leapyear][rulep->r_mon - 1])