1 /* @(#)e_jn.c 5.1 93/09/24 */
2 /*
3  * ====================================================
4  * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
5  *
6  * Developed at SunPro, a Sun Microsystems, Inc. business.
7  * Permission to use, copy, modify, and distribute this
8  * software is freely granted, provided that this notice
9  * is preserved.
10  * ====================================================
11  */
12 
13 #include <sys/cdefs.h>
14 #if defined(LIBM_SCCS) && !defined(lint)
15 __RCSID("$NetBSD: e_jn.c,v 1.14 2010/11/29 15:10:06 drochner Exp $");
16 #endif
17 
18 /*
19  * __ieee754_jn(n, x), __ieee754_yn(n, x)
20  * floating point Bessel's function of the 1st and 2nd kind
21  * of order n
22  *
23  * Special cases:
24  *        y0(0)=y1(0)=yn(n,0) = -inf with division by zero signal;
25  *        y0(-ve)=y1(-ve)=yn(n,-ve) are NaN with invalid signal.
26  * Note 2. About jn(n,x), yn(n,x)
27  *        For n=0, j0(x) is called,
28  *        for n=1, j1(x) is called,
29  *        for n<x, forward recursion us used starting
30  *        from values of j0(x) and j1(x).
31  *        for n>x, a continued fraction approximation to
32  *        j(n,x)/j(n-1,x) is evaluated and then backward
33  *        recursion is used starting from a supposed value
34  *        for j(n,x). The resulting value of j(0,x) is
35  *        compared with the actual value to correct the
36  *        supposed value of j(n,x).
37  *
38  *        yn(n,x) is similar in all respects, except
39  *        that forward recursion is used for all
40  *        values of n>1.
41  *
42  */
43 
44 #include "namespace.h"
45 #include "math.h"
46 #include "math_private.h"
47 
48 static const double
49 invsqrtpi=  5.64189583547756279280e-01, /* 0x3FE20DD7, 0x50429B6D */
50 two   =  2.00000000000000000000e+00, /* 0x40000000, 0x00000000 */
51 one   =  1.00000000000000000000e+00; /* 0x3FF00000, 0x00000000 */
52 
53 static const double zero  =  0.00000000000000000000e+00;
54 
55 double
__ieee754_jn(int n,double x)56 __ieee754_jn(int n, double x)
57 {
58           int32_t i,hx,ix,lx, sgn;
59           double a, b, temp, di;
60           double z, w;
61 
62           temp = 0;
63     /* J(-n,x) = (-1)^n * J(n, x), J(n, -x) = (-1)^n * J(n, x)
64      * Thus, J(-n,x) = J(n,-x)
65      */
66           EXTRACT_WORDS(hx,lx,x);
67           ix = 0x7fffffff&hx;
68     /* if J(n,NaN) is NaN */
69           if((ix|((u_int32_t)(lx|-lx))>>31)>0x7ff00000) return x+x;
70           if(n<0){
71                     n = -n;
72                     x = -x;
73                     hx ^= 0x80000000;
74           }
75           if(n==0) return(__ieee754_j0(x));
76           if(n==1) return(__ieee754_j1(x));
77           sgn = (n&1)&(hx>>31);         /* even n -- 0, odd n -- sign(x) */
78           x = fabs(x);
79           if((ix|lx)==0||ix>=0x7ff00000)          /* if x is 0 or inf */
80               b = zero;
81           else if((double)n<=x) {
82                     /* Safe to use J(n+1,x)=2n/x *J(n,x)-J(n-1,x) */
83               if(ix>=0x52D00000) { /* x > 2**302 */
84     /* (x >> n**2)
85      *        Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)
86      *        Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)
87      *        Let s=sin(x), c=cos(x),
88      *              xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then
89      *
90      *                 n      sin(xn)*sqt2        cos(xn)*sqt2
91      *              ----------------------------------
92      *                 0       s-c                 c+s
93      *                 1      -s-c                -c+s
94      *                 2      -s+c                -c-s
95      *                 3       s+c                 c-s
96      */
97                     switch(n&3) {
98                         case 0: temp =  cos(x)+sin(x); break;
99                         case 1: temp = -cos(x)+sin(x); break;
100                         case 2: temp = -cos(x)-sin(x); break;
101                         case 3: temp =  cos(x)-sin(x); break;
102                     }
103                     b = invsqrtpi*temp/sqrt(x);
104               } else {
105                   a = __ieee754_j0(x);
106                   b = __ieee754_j1(x);
107                   for(i=1;i<n;i++){
108                         temp = b;
109                         b = b*((double)(i+i)/x) - a; /* avoid underflow */
110                         a = temp;
111                   }
112               }
113           } else {
114               if(ix<0x3e100000) {       /* x < 2**-29 */
115     /* x is tiny, return the first Taylor expansion of J(n,x)
116      * J(n,x) = 1/n!*(x/2)^n  - ...
117      */
118                     if(n>33)  /* underflow */
119                         b = zero;
120                     else {
121                         temp = x*0.5; b = temp;
122                         for (a=one,i=2;i<=n;i++) {
123                               a *= (double)i;               /* a = n! */
124                               b *= temp;                    /* b = (x/2)^n */
125                         }
126                         b = b/a;
127                     }
128               } else {
129                     /* use backward recurrence */
130                     /*                            x      x^2      x^2
131                      *  J(n,x)/J(n-1,x) =  ----   ------   ------   .....
132                      *                            2n  - 2(n+1) - 2(n+2)
133                      *
134                      *                            1      1        1
135                      *  (for large x)   =  ----  ------   ------   .....
136                      *                            2n   2(n+1)   2(n+2)
137                      *                            -- - ------ - ------ -
138                      *                             x     x         x
139                      *
140                      * Let w = 2n/x and h=2/x, then the above quotient
141                      * is equal to the continued fraction:
142                      *                      1
143                      *        = -----------------------
144                      *                         1
145                      *           w - -----------------
146                      *                              1
147                      *                w+h - ---------
148                      *                         w+2h - ...
149                      *
150                      * To determine how many terms needed, let
151                      * Q(0) = w, Q(1) = w(w+h) - 1,
152                      * Q(k) = (w+k*h)*Q(k-1) - Q(k-2),
153                      * When Q(k) > 1e4  good for single
154                      * When Q(k) > 1e9  good for double
155                      * When Q(k) > 1e17 good for quadruple
156                      */
157               /* determine k */
158                     double t,v;
159                     double q0,q1,h,tmp; int32_t k,m;
160                     w  = (n+n)/(double)x; h = 2.0/(double)x;
161                     q0 = w;  z = w+h; q1 = w*z - 1.0; k=1;
162                     while(q1<1.0e9) {
163                               k += 1; z += h;
164                               tmp = z*q1 - q0;
165                               q0 = q1;
166                               q1 = tmp;
167                     }
168                     m = n+n;
169                     for(t=zero, i = 2*(n+k); i>=m; i -= 2) t = one/(i/x-t);
170                     a = t;
171                     b = one;
172                     /*  estimate log((2/x)^n*n!) = n*log(2/x)+n*ln(n)
173                      *  Hence, if n*(log(2n/x)) > ...
174                      *  single 8.8722839355e+01
175                      *  double 7.09782712893383973096e+02
176                      *  long double 1.1356523406294143949491931077970765006170e+04
177                      *  then recurrent value may overflow and the result is
178                      *  likely underflow to zero
179                      */
180                     tmp = n;
181                     v = two/x;
182                     tmp = tmp*__ieee754_log(fabs(v*tmp));
183                     if(tmp<7.09782712893383973096e+02) {
184                         for(i=n-1,di=(double)(i+i);i>0;i--){
185                             temp = b;
186                               b *= di;
187                               b  = b/x - a;
188                             a = temp;
189                               di -= two;
190                         }
191                     } else {
192                         for(i=n-1,di=(double)(i+i);i>0;i--){
193                             temp = b;
194                               b *= di;
195                               b  = b/x - a;
196                             a = temp;
197                               di -= two;
198                         /* scale b to avoid spurious overflow */
199                               if(b>1e100) {
200                                   a /= b;
201                                   t /= b;
202                                   b  = one;
203                               }
204                         }
205                     }
206                     z = __ieee754_j0(x);
207                     w = __ieee754_j1(x);
208                     if (fabs(z) >= fabs(w))
209                               b = (t*z/b);
210                     else
211                               b = (t*w/a);
212               }
213           }
214           if(sgn==1) return -b; else return b;
215 }
216 
217 double
__ieee754_yn(int n,double x)218 __ieee754_yn(int n, double x)
219 {
220           int32_t i,hx,ix,lx;
221           int32_t sign;
222           double a, b, temp;
223 
224           temp = 0;
225           EXTRACT_WORDS(hx,lx,x);
226           ix = 0x7fffffff&hx;
227     /* if Y(n,NaN) is NaN */
228           if((ix|((u_int32_t)(lx|-lx))>>31)>0x7ff00000) return x+x;
229           if((ix|lx)==0) return -one/zero;
230           if(hx<0) return zero/zero;
231           sign = 1;
232           if(n<0){
233                     n = -n;
234                     sign = 1 - ((n&1)<<1);
235           }
236           if(n==0) return(__ieee754_y0(x));
237           if(n==1) return(sign*__ieee754_y1(x));
238           if(ix==0x7ff00000) return zero;
239           if(ix>=0x52D00000) { /* x > 2**302 */
240     /* (x >> n**2)
241      *        Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)
242      *        Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)
243      *        Let s=sin(x), c=cos(x),
244      *              xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then
245      *
246      *                 n      sin(xn)*sqt2        cos(xn)*sqt2
247      *              ----------------------------------
248      *                 0       s-c                 c+s
249      *                 1      -s-c                -c+s
250      *                 2      -s+c                -c-s
251      *                 3       s+c                 c-s
252      */
253                     switch(n&3) {
254                         case 0: temp =  sin(x)-cos(x); break;
255                         case 1: temp = -sin(x)-cos(x); break;
256                         case 2: temp = -sin(x)+cos(x); break;
257                         case 3: temp =  sin(x)+cos(x); break;
258                     }
259                     b = invsqrtpi*temp/sqrt(x);
260           } else {
261               u_int32_t high;
262               a = __ieee754_y0(x);
263               b = __ieee754_y1(x);
264           /* quit if b is -inf */
265               GET_HIGH_WORD(high,b);
266               for(i=1;i<n&&high!=0xfff00000;i++){
267                     temp = b;
268                     b = ((double)(i+i)/x)*b - a;
269                     GET_HIGH_WORD(high,b);
270                     a = temp;
271               }
272           }
273           if(sign>0) return b; else return -b;
274 }
275