Create a new image from file or URL

imagecreatefromgif
imagecreatefrompng
GD and Image Functions
PHP Manual

# imagecreatefromjpeg

(PHP 4, PHP 5)

imagecreatefromjpeg — Create a new image from file or URL

### Description

resource imagecreatefromjpeg ( string `$filename` )

imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.

Tip

A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename. See the List of Supported Protocols/Wrappers for links to information about what abilities the various wrappers have, notes on their usage, and information on any predefined variables they may provide.

### Parameters

`filename`

  Path to the JPEG image.

### Return Values

Returns an image resource identifier on success, `FALSE` on errors.

### Examples

Example #1 Example to handle an error during loading of a JPEG

`<?php
function LoadJpeg($imgname)
{
/* Attempt to open */
$im = @imagecreatefromjpeg($imgname);
/* See if it failed */
if(!$im)
{
/* Create a black image */
$im = imagecreatetruecolor(150, 30);
$bgc = imagecolorallocate($im, 255, 255, 255);
$tc = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
/* Output an error message */
imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
}
return $im;
}
header('Content-Type: image/jpeg');
$img = LoadJpeg('bogus.image');
imagejpeg($img);
imagedestroy($img);
?>`

The above example will output something similar to:

### Notes

> Note: JPEG support is only available if PHP was compiled against GD-1.8 or later.

Warning

Windows versions of PHP prior to PHP 4.3.0 do not support access of remote files via this function, even if allow_url_fopen is enabled.

imagecreatefromgif
imagecreatefrompng
GD and Image Functions
PHP Manual